Question: This guestionben mdfied slightby Jor exam akins urposes Workers shaled how mutation trepK ney (MF…


This guestionben mdfied slightby Jor exam akins urposes Workers shaled how mutation trepK ney (MF) was allected by deliciencies in a variety cd genes เด E coli They studied MF in a simple way. Ecoli are seusitive to killed by) the antihiotic rifamycis (rif or rif) However, approximasely 1/10 ( 1o%E co are resistant to nifamycin rif)which can be the result of a variety of bs substitution mutations in a particular gene oGpolt) changes in mutation troquency(İ.e , increases from 10.9) 1rV-> rv gives a measure of the nic ermome is being mutated. Mutation firequency is simply the ratio lit Vlat n Spontancoes mutation frequency was studied in a variety encodes the MutH prolein (etc) of cells with different genotypes (Table D. The muai TableI Genotype of Esel Spontaneous Mutation Frequency x10-7 1x10 1x10 1x10 Il.2a. Based on what you know about these genes, explain the results in Table I. Be sure to explain explicidly w hat each of these genes does There is one gene in this table that you have not heard about. Simply mention which it is in your answer to 2a. You will have to conclude something about this gene after you consider the results in Table 11 Several other strains of E.coli- notably double mutants-were also tested (Table I1) Genotype of F. col mutH/mutL-Imuts /mutr/dam Table I1 Spontaneous Mutation Frequency 1x10-7 1x10-7 1x10 2x10 11.2.b. Rationalize the results in Table I1. In the next data set (Table II),a strain of E. coll was used whose genomic DNA was mut L SIY idamt (wild type) in each case. To this cell was added a multi-copy plasmid that contained a cloned copy of a gene; e.g., the second line. In each case, the cloned gene is expressed normally, although this multi-copy plasmids was present at-40 copies per cell. In each f the entries in Table III, mutation frequency was measured. Table1프 Spontaneous Mutation Frequency Genotype of E coli 1x10-9 1x10 + no plasmid + muth containing plasmid +muti containing plasmid +muts containing plasmid + muty containing plasmid +dam containing plasmid 0.5x10 1x10-9 1x10-9 1x10-7 III.2.c. Rationalize the results in Table I11.

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This guestionben mdfied slightby Jor exam akins urposes Workers shaled how mutation trepK ney (MF) was allected by deliciencies in a variety cd genes เด E coli They studied MF in a simple way. Ecoli are seusitive to killed by) the antihiotic rifamycis (rif or rif) However, approximasely 1/10 ( 1o%E co are resistant to nifamycin rif)which can be the result of a variety of bs substitution mutations in a particular gene oGpolt) changes in mutation troquency(İ.e , increases from 10.9) 1rV-> rv' gives a measure of the nic ermome is being mutated. Mutation firequency is simply the ratio lit Vlat n Spontancoes mutation frequency was studied in a variety encodes the MutH prolein (etc) of cells with different genotypes (Table D. The muai TableI Genotype of Esel Spontaneous Mutation Frequency x10-7 1×10 1×10 1×10 Il.2a. Based on what you know about these genes, explain the results in Table I. Be sure to explain explicidly w hat each of these genes does There is one gene in this table that you have not heard about. Simply mention which it is in your answer to 2a. You will have to conclude something about this gene after you consider the results in Table 11 Several other strains of E.coli- notably double mutants-were also tested (Table I1) Genotype of F. col mutH/mutL-Imuts' /mutr/dam Table I1 Spontaneous Mutation Frequency 1×10-7 1×10-7 1×10 2×10 11.2.b. Rationalize the results in Table I1. In the next data set (Table II),a strain of E. coll was used whose genomic DNA was mut L S'IY idamt (wild type) in each case. To this cell was added a multi-copy plasmid that contained a cloned copy of a gene; e.g., the second line. In each case, the cloned gene is expressed normally, although this "multi-copy" plasmids was present at-40 copies per cell. In each f the entries in Table III, mutation frequency was measured. Table1프 Spontaneous Mutation Frequency Genotype of E coli 1×10-9 1×10 + no plasmid + muth containing plasmid +muti containing plasmid +muts containing plasmid + muty containing plasmid +dam containing plasmid 0.5×10 1×10-9 1×10-9 1×10-7 III.2.c. Rationalize the results in Table I11.

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