Question: PART LQuestion M2.(15 points studied MF in a “myde way E .vd, a” w”uti” to ained by) do seata-e f…


PART LQuestion M2.(15 points studied MF in a myde way E .vd, a wuti to ained by) do seata-e fitsmycia (rif sabssitation mutations in a particular gene Upolt Thix estion asbeen modified slighty form ing poes , y i ธ6..เม which the E col geome is being musated Mutation freqency ie simpty t fit viet encodes the Muti protein fetc.) Table I Genotype of col Spontaneous Hrtatton Froancy 1*16 e16-7 Ix10 1o-7 1819-7 s10-7 . /dam 111.2a. Based on what you know about these genes, explain the resuits in Tode .e what each of these genes does t esplain esplicly There is one gene in this table that you have not heand afeoet Simly mention which it ie in yom amower to 2a. You will have to conclude something aboot this gene after yoe comsider the results in Table Several other strains of E.colu-notaly double mutants-were af tested Table Table I Genotype of E. coli Spontaneons mitation Propioney Ix10 Ix16-7 1x10-7 2M10-7 utH/mutt /muts/mutY/dam 111.2.b. Rationalize the results in Table II. In the next data set (Table II), a strain of E.colf was used whewe genomic DNA was multn ot mutH genc in the second line. In each case, the cloned gene is es ) in each case. To this cell was added a multi-copy plasmid that contained cloned copy of ส gene; e plasmids was present at -40 copies per cell. In cach of the entries in Talde IIl, mntaticon fregneney was messered pressed wemully, althongh this mele copy Table III Genotype of B. coli Spont aneous Hutat Lon Fregisey t no plasmid +mutH containing plasmid mutL containing plasmid + muts+ containing plasmid muty containing plasmid dam containing plasmid 1x10-9 Ix10-9 0. Sx10-9 Ix10-9 1x10-, 1x10-7 111.2c. Rationalize the results in Table I11

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PART LQuestion M2.(15 points studied MF in a "myde way E .vd, a" w"uti" to ained by) do seata-e fitsmycia (rif sabssitation mutations in a particular gene Upolt Thix estion asbeen modified slighty form ing poes , y i ธ6..เม which the E col geome is being musated Mutation freqency ie simpty t fit viet encodes the Muti protein fetc.) Table I Genotype of col Spontaneous Hrtatton Froancy 1*16 e16-7 Ix10 1o-7 1819-7 s10-7 . /dam 111.2a. Based on what you know about these genes, explain the resuits in Tode .e what each of these genes does t esplain esplicly There is one gene in this table that you have not heand afeoet Simly mention which it ie in yom amower to 2a. You will have to conclude something aboot this gene after yoe comsider the results in Table Several other strains of E.colu-notaly double mutants-were af tested Table Table I Genotype of E. coli Spontaneons mitation Propioney Ix10 Ix16-7 1×10-7 2M10-7 utH/mutt /muts/mutY/dam 111.2.b. Rationalize the results in Table II. In the next data set (Table II), a strain of E.colf was used whewe genomic DNA was multn ot mutH genc in the second line. In each case, the cloned gene is es ) in each case. To this cell was added a multi-copy plasmid that contained cloned copy of ส gene; e plasmids was present at -40 copies per cell. In cach of the entries in Talde IIl, mntaticon fregneney was messered pressed wemully, althongh this "mele copy Table III Genotype of B. coli Spont aneous Hutat Lon Fregisey t no plasmid +mutH containing plasmid mutL containing plasmid + muts+ containing plasmid muty containing plasmid dam containing plasmid 1×10-9 Ix10-9 0. Sx10-9 Ix10-9 1×10-, 1×10-7 111.2c. Rationalize the results in Table I11

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