Question: Figures below, assume that all E. coli cells begin in a no growth state (lack In the the cells ha…


figures below, assume that all E. coli cells begin in a no growth state (lack In the the cells have one oriC per cell at t-Onin AlにOuin, the same high level of nutrients carbon, nitrogen, phosphorus, ete.) is added to each of the cells in panels A, B. C and D (sources of Remembera oriC is found at a unique site, and these data are showing results for oriC only, and ne for any other portion of the E. coli chromosome. I. a Rationalize the shape and timing of the curve in the case of fully wild type E. coll cells A complete answer will include the name(s) of any protein(s) that directly affect the pr that oriC will become active, along with how this(these) protein(s) levels) might be changing following the addition of nutrients. (The answer is straightforward, and you should not worry about some deep subklety) b. Redraw this figure in your Blue Book and show what will happen with the curve at longer times when cell division occurs. 2. The cells in Panel B have a mutation in the promoter of the dnad gene that results in higher levels of mRNA for dnaA when transcription occurs. Rationalize all aspects of the shape and timing of the curve in Panel B. NOTE: In Panels B, C and D, some increases appear curved, which results from imperfect cell synchrony, along with the cells not having sufficient nutrients to sustain increased DNA synthesis. You do not have to rationalize this curvature. Pay more attention to the timing of when oriC levels change. 3. Rationalize the shape and timing of the curve in cells that are seqA (deficient) (Panel C). 4. Rationalize the shape and timing of the curve in cells where the dnaA gene was moved from its usual position on the E. coli chromosome to 17 on the E.coli chromosome (Panel D). 0 10 20 30 40 50 60min AI Number 2.o 1.0TT oric in a cell 2.0 1.0 2.0 1.0 T 2.01 1.0 0 10 20 30 40 50 60min

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figures below, assume that all E. coli cells begin in a no growth state (lack In the the cells have one oriC per cell at t-Onin AlにOuin, the same high level of nutrients carbon, nitrogen, phosphorus, ete.) is added to each of the cells in panels A, B. C and D (sources of Remembera oriC is found at a unique site, and these data are showing results for oriC only, and ne for any other portion of the E. coli chromosome. I. a Rationalize the shape and timing of the curve in the case of fully wild type E. coll cells A complete answer will include the name(s) of any protein(s) that directly affect the pr that oriC will become active, along with how this(these) protein(s) levels) might be changing following the addition of nutrients. (The answer is straightforward, and you should not worry about some deep subklety) b. Redraw this figure in your Blue Book and show what will happen with the curve at longer times when cell division occurs. 2. The cells in Panel B have a mutation in the promoter of the dnad gene that results in higher levels of mRNA for dnaA when transcription occurs. Rationalize all aspects of the shape and timing of the curve in Panel B. NOTE: In Panels B, C and D, some increases appear curved, which results from imperfect cell synchrony, along with the cells not having sufficient nutrients to sustain increased DNA synthesis. You do not have to rationalize this curvature. Pay more attention to the timing of when oriC levels change. 3. Rationalize the shape and timing of the curve in cells that are seqA (deficient) (Panel C). 4. Rationalize the shape and timing of the curve in cells where the dnaA gene was moved from its usual position on the E. coli chromosome to 17' on the E.coli chromosome (Panel D). 0 10 20 30 40 50 60min AI Number 2.o 1.0TT oric in a cell 2.0 1.0 2.0 1.0 T 2.01 1.0 0 10 20 30 40 50 60min

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